题解 | #公共子串计算#
公共子串计算
http://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String a = scanner.next();
String b = scanner.next();
System.out.println(maxCommonSubstringLength(a, b));
}
public static int maxCommonSubstringLength(String a, String b) {
if (a == null || b == null) {
return 0;
}
int maxLength = 0;
int aLength = a.length();
int bLength = b.length();
int[][] dp = new int[aLength+1][bLength+1];
for (int i = 1; i <= aLength; ++i) {
for (int j = 1; j <= bLength; ++j) {
if (a.charAt(i-1) == b.charAt(j-1)) {
dp[i][j] = dp[i-1][j-1] + 1;
maxLength = Math.max(dp[i][j], maxLength);
}
}
}
return maxLength;
}
} 