JZ9 跳台阶扩展问题
跳台阶扩展问题
https://www.nowcoder.com/practice/22243d016f6b47f2a6928b4313c85387?tpId=13&&tqId=11162&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking
public class Solution {
public int jumpFloorII(int target) {
return (int)Math.pow(2,target-1);
}
}f(n)=f(n-1)+f(n-2)+...+f(1)
f(n-1)=f(n-2)+...f(1)
得:f(n)=2f(n-1)=2^2f(n-2) = 2^(n-1)*1
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