题解 | #字符串加密#

def fun(key, s):
    alphabet = 'abcdefghijklmnopqrstuvwxyz'
    key = key.lower()
    newkey = ''
    newalphabet = alphabet
    #得到密钥
    for i, k in enumerate(key):
        if i == key.index(k):#实现了去重操作！如key.index('l') = 4 (只返回第一次出现时的位置！)
            newkey += k
            newalphabet = newalphabet.replace(k, '')
    newkey = newkey + newalphabet
    #得到密文
    d = dict(zip(alphabet, newkey))#alphabet是d.keys() newkey是d.values() 
    #字母字符的大小写状态保留 空格也要保留
    temp = []
    for i in s:
        if i == ' ':
            temp.append(' ')
        elif i.islower():
            temp.append(d[i])
        else:
            i = i.lower()
            temp.append(d[i].upper())
    res = ''.join(temp) 
    return res 


while True:
    try:
        key = input()
        s = input()
        print(fun(key, s))
    except:
        break
        '''
TRAILBLAZERS
Attack AT DAWN
'''