题解 | #提取不重复的整数#
提取不重复的整数
http://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1
include
using namespace std;
int main(){
int n,t;
int k[10];
cin >> n;
for(int i=0;i<10;i++)
k[i]=-1;
while (n) {
t = n % 10;
if (k[t] == -1) {
k[t] = t;
cout << k[t];
}
n /= 10;
}
}