题解 | #旋转数组的最小数字#
旋转数组的最小数字
http://www.nowcoder.com/practice/9f3231a991af4f55b95579b44b7a01ba
class Solution {
public:
int minNumberInRotateArray(vector<int> rotateArray) {
int start = 0;
int end = rotateArray.size()-1;
while(start<end)
{
int mid = (start+end)/2;
if(rotateArray[mid] > rotateArray[end])
{
start = mid+1;
}
else if(rotateArray[mid] < rotateArray[end])
{
end = mid;
}
else{
// mid++;
end--;
}
}
return rotateArray[start];
}
};

