<span>leetcode-609 Find Duplicate File in System</span>

Given a list of directory info including directory path, and all the files with contents in this directory, you need to find out all the groups of duplicate files in the file system in terms of their paths.

A group of duplicate files consists of at least two files that have exactly the same content.

A single directory info string in the input list has the following format:

"root/d1/d2/.../dm f1.txt(f1_content) f2.txt(f2_content) ... fn.txt(fn_content)"

It means there are n files (f1.txt, f2.txt ... fn.txt with content f1_content, f2_content ... fn_content, respectively) in directory root/d1/d2/.../dm. Note that n >= 1 and m >= 0. If m = 0, it means the directory is just the root directory.

The output is a list of group of duplicate file paths. For each group, it contains all the file paths of the files that have the same content. A file path is a string that has the following format:

"directory_path/file_name.txt"

输入输出实例：

Input:
["root/a 1.txt(abcd) 2.txt(efgh)", "root/c 3.txt(abcd)", "root/c/d 4.txt(efgh)", "root 4.txt(efgh)"]
Output:  
[["root/a/2.txt","root/c/d/4.txt","root/4.txt"],["root/a/1.txt","root/c/3.txt"]]



本题题意比较简单，就是找出含有重复内容的文件归类输出就行了。

class Solution:
    def findDuplicate(self, paths: List[str]) -> List[List[str]]:
        def seperateStr(path):
            return path.split()
        dic = {}
        for path in paths:
            pa = seperateStr(path)
            pa[0] = pa[0] + "/"
            prefix = pa[0]
            for i in range(1,len(pa)):
                item = pa[i].find("(")
                suffix = pa[i][:item]
                content = pa[i][item+1:len(pa[i])-1]
                if content in dic:
                    dic[content].append(prefix + suffix)
                else:
                    dic[content] = [prefix + suffix]
        result = []
        for i in dic:
            if len(dic[i]) > 1:
                result.append(dic[i])
        return result