A. Tile Painting

链接:https://codeforces.com/contest/1242/problem/A

Ujan has been lazy lately, but now has decided to bring his yard to good shape. First, he decided to paint the path from his house to the gate.

The path consists of nn consecutive tiles, numbered from 11 to nn. Ujan will paint each tile in some color. He will consider the path aesthetic if for any two different tiles with numbers ii and jj, such that |j−i||j−i| is a divisor of nn greater than 11, they have the same color. Formally, the colors of two tiles with numbers ii and jj should be the same if |i−j|>1|i−j|>1 and nmod|i−j|=0nmod|i−j|=0 (where xmodyxmody is the remainder when dividing xx by yy).

Ujan wants to brighten up space. What is the maximum number of different colors that Ujan can use, so that the path is aesthetic?

Input

The first line of input contains a single integer nn (1≤n≤10121≤n≤1012), the length of the path.

Output

Output a single integer, the maximum possible number of colors that the path can be painted in.

Examples

input

Copy

4

output

Copy

2

input

Copy

5

output

Copy

5

Note

In the first sample, two colors is the maximum number. Tiles 11 and 33 should have the same color since 4mod|3−1|=04mod|3−1|=0. Also, tiles 22and 44 should have the same color since 4mod|4−2|=04mod|4−2|=0.

In the second sample, all five colors can be used.

题解:很有意思的一道题,首先不难发现如果是质数直接输出质数,否则只需判断是否只有一个质因子就行,如果只有一个质因子就输出这个质因子,否则输出1

#include<bits/stdc++.h>
using namespace std;
long long n;
int main()
{
	cin>>n;
	for(long long i=2;i*i<=n;i++)
	{
		if(n%i==0)
		{
			while(n%i==0)
			n/=i;
			if(n!=1)
			cout<<1;
			else
			cout<<i;
			return 0;
		}
	}
	cout<<n; 
	
}

 

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rbjjj:太杂了吧,同学,项目似乎都没深度,都是api调度耶,分层架构思想没有体现出来了,前端没有前端优化前端工程化体现,后端微服务以及分层架构没体现以及数据安全也没体现,核心再改改,注重于计算机网络,工程化,底层原理吧
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11-04 19:05
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东莞城市学院 单片机
不知道怎么取名字_:你这个要实习两年?哪有这么久的,感觉就是即使你毕业了,但还按实习的话,是不是不用给你缴社保公积金啥的
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