字符串加解密

存粹考代码

思路：

1. 建立两个容器，加密字母大小变换后推，数字后推，其他不变
2. 解密字母大小变换前推，数字前推，其他不变

#include<iostream>
#include<string>
#include<vector>
using namespace std;
vector<char> v1;
vector<char> v2;
void EnCode(char ch)
{
    if (ch>= 'a' && ch <= 'z')
    {  
        if (ch == 'z') ch = 'A';
        else
            ch= ch - 31;
    }
    else if (ch >= 'A' && ch <= 'Z')
    {
        if (ch == 'Z') ch = 'a';
        else
            ch = ch +33;
    }
    else if (ch >= '0' && ch <= '9')
    {
        if (ch == '9') ch = '0';
        else
            ch = ch+1;
    }
    v1.push_back(ch);
}
void DeCode(char ch)
{
    if (ch >= 'a' && ch <= 'z')
    {
        if (ch == 'a') ch = 'Z';
        else
            ch = ch - 33;
    }
    else if (ch >= 'A' && ch <= 'Z')
    {
        if (ch =='A') ch = 'z';
        else
            ch = ch + 31;
    }
    else if (ch >= '0' && ch <= '9')
    {
        if (ch == '0') ch = '9';
        else
            ch = ch - 1;
    }
    v2.push_back(ch);
}
int main()
{
    string str1;
    string str2;
    while (getline(cin, str1))
    {
        getline(cin, str2);
        if (str1 == "" || str2 == "") break;
        int len1 = str1.size();
        int len2 = str2.size();
        for (int i = 0; i < len1; i++)
        {
            EnCode(str1[i]);
        }
        for (int i = 0; i < len2; i++)
        {
            DeCode(str2[i]);
        }
        for (int i = 0; i < v1.size(); i++)
            cout << v1[i];
        cout << endl;
        for (int i = 0; i < v2.size(); i++)
            cout << v2[i];
        cout << endl;
        v1.clear();
        v2.clear();
    }
}