题解 | #等差数列#
等差数列
http://www.nowcoder.com/practice/f792cb014ed0474fb8f53389e7d9c07f
#include <iostream>
using namespace std;
int main()
{
int a;
while(cin>>a)
{
cout<<(2+2+3*(a-1))*a/2;
}
return(0);
}
using namespace std;
int main()
{
int a;
while(cin>>a)
{
cout<<(2+2+3*(a-1))*a/2;
}
return(0);
}
投递东软集团等公司10个岗位
